Mathematics: How can I solve this question

How can I solve this question - id6659197, shelbyetheridge1011s

Ответ:

agray062103

27.01.2022

B. $\frac{1}{2} sin2x + c$

Step-by-step explanation:

$\int \frac{1 - { tan}^{2}x }{1 + { tan}^{2}x } dx \\ \\ = \int \frac{1 - \frac{ {sin}^{2}x }{ {cos}^{2}x } }{ {sec}^{2}x } dx\\ \\ = \int \frac{ {cos}^{2} x - {sin}^{2}x }{ {cos}^{2} x \times {sec}^{2} x }dx \\ \\ = \int \frac{cos \: 2x}{1} dx \\ \\ = \int {cos \: 2x}dx \\ \\ = \frac{1}{2} sin2x + c$

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Ответ:

hopeR13

27.01.2022

Mathematics

Step-by-step explanation:

1 + tan²X = sec²X

(1 - tan²X)/sec²X

cos²X - sin²X

cos2X

Integral of cos2X

= sin2X ÷ 2 + c

= ½sin2X + c

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Ответ:

nnance4784

09.06.2023

Mathematics

In attempt to find a non-violent alternative for reducing Hell's overpopulation, the daughter of Lucifer opens a rehabilitation hotel that offers a group of misfit demons a chance at redemption.

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