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CarleySamuel
11.10.2019 •
Mathematics
How do you solve this equation, 5s^2-14s-3=0
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Ответ:
5s^2 - 14s - 3 = 0
(5s + 1)(s - 3) = 0
5s + 1 = 0
or
s - 3 = 0
Therefore
s = -1/5
or
s = 3
Ответ:
B
Step-by-step explanation:
h(t) = (t + 3)² + 5
A) h(t) = (t + 3)² + 5 -2 ≤ t ≤ 0
average rate of change in h over the change in t is given as:
It does not have a negative average rate of change
B) A) h(t) = (t + 3)² + 5 -4 ≤ t ≤ -3
average rate of change in h over the change in t is given as:
It have a negative average rate of change
c) A) h(t) = (t + 3)² + 5 -3 ≤ t ≤ 4
average rate of change in h over the change in t is given as:
It does not have a negative average rate of change
D) h(t) = (t + 3)² + 5 1 ≤ t ≤ 4
average rate of change in h over the change in t is given as:
It does not have a negative average rate of change