How does f(x) = 3 ^x change over the interval x = 4 to x= 5

f(x) = 3^x increases steadily on the interval [4,5].

Step-by-step explanation:

This exponential function f(x) = 3^x has a positive base (3) which is larger than 1.  Thus, this function continues to increase as x increases, including the case where x increases from 4 to 5.

Part A

The expression in terms of 't' representing the number of radians Josh has swept since the ride started is 3·t rad

Part B

The time to complete one revolution is (2·π/3) minutes

Part C.

The function 'f' that determines Josh's height above the ground (in feet) in terms of 't' is, f(t) = 44·sin(3·t + π/2) + 50

Step-by-step explanation:

The radius of the Ferris wheel = 44 foot

The height of the Ferris wheel above the ground = 50 feet

The direction of rotation of the Ferris wheel = CCW

The angular speed of the Ferris wheel, ω = 3 radians per minute

The position from which Josh boards the Ferris wheel = 3-O'Clock

The number of minutes since the ride started started = t

Part A

The expression in terms of 't' to represent the number of radians Josh has swept since the ride started = ω × t = 3 × t rad = 3·t rad

Part B

One complete revolution = 2·π radians

The time to complete one revolution = 2·π/ω = 2·π/(3 rad/minute) = (2·π/3) minutes =  ·π minutes ≈ 2.0943951 minutes

Part C.

The height, 'h', of the Ferris wheel is given by the following sinusoidal relation

f(t) = A·sin(B·t + C) + D

Where;

A = The amplitude = The radius of the Ferris wheel = 44 ft.

The period, T = (2·π/3) minute

B = 2·π/T = 3

t = The time in minutes

D = The Ferris wheel's height above ground = 50 ft.

C = The horizontal shift = π/2 (Josh boards the Ferris wheel at t = 3-O'Clock which is the midline, a rotation of π/2 from the lowermost end of the Ferris wheel)

Therefore the function that determines Josh's height above the ground (in feet) in terms of 't' is presented as follows;

f(t) = 44·sin(3·t + π/2) + 50