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tommyaberman
02.09.2019 •
Mathematics
How i can solve this integral ∫ dx / akar 25 - 16x^2 ? i really need your , you.
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Ответ:
∫ 1/√(1 - x²/a) dx = √a arcsin(x/√a)
So pull a factor of 5 out of the square root to get
1/5 ∫ 1/√(1 - 16 x²/25) dx
= 1/4 arcsin(4 x/5)
Ответ:
Ответ:
couldnt draw sorry but heres the answers for a
Step-by-step explanation:
for x = -2
x+y= 6
-2+8=6
so y=8
for x=-1 do the same and y= 7
for x =0 y=6
for x=1 y=5
for x=2 y=4
for x=3 y=3