How many gallons of pure water should be evaporated from 160 gallons of a solution containing 12% salt so that the remaining solution contains 20% salt?

X= # gallons of pure water that should be evaporated

The total amount of salt must be equal before and after evaporation.
STEP 1
BEFORE EVAPORATION: multiply the percent of salt in the solution before evaporation by the total gallons of solution
= 12% * 160 gallonsconvert 12% to decimal form (12% ÷ 100)
= 0.12 * 60

STEP 2
AFTER EVAPORATION: subtract the number of gallons of pure water that should be evaporated from the total number of gallons of the solution and multiply by the percent of salt in the solution after evaporation

= 20% * (160 - x)convert 20% to decimal form (20% ÷ 100)
= 0.20(160 - x)

STEP 3
Set the before & after evaporation equations equal to one another to solve for x.
0.12 * 160= 0.20(160 - x)multiply 0.20 by each term in parentheses
19.2= (0.20 * 160) + (0.20 * -x)multiply in parentheses
19.2 = 32 - 0.20xsubtract 32 from both sides
-12.8= -0.20xdivide both sides by -0.20
64 gallons= x

CHECK:substitute x= 64 into the step 3 equation
0.12 * 160= 0.20(160 - x)19.2= 0.20(160 - 64)subtract in parentheses19.2= 0.20(96)19.2= 19.2

ANSWER: 64 gallons of pure water should be evaporated.
Hope this helps!  :)

750 Books Per Year

Step-by-step explanation:

For this problem, we will be using the standard Rate Of Change formula that we use for graphs:

RoC = (y2 - y1) / (x2 - x1)

y = books

x = year

By plugging in the given values:

RoC = (19000 - 16000) / (1999 -1995)

RoC = 3000 / 4

RoC = 750