How many whole numbers leave a remainder of 2 when divided into 56, and a remainder of 1 when divided into 28? a.) 0 b.) 2 c.) 3 d.) 4?

56 would have a remainder of 2 using multiples of 3

56/3 = 18 remainder 2

56/6 = 9 remainder 2

56/9 = 6 remainder 2

56/18 = 3 remainder 2

56/27 = 2 remainder 2

Now divide 28 by the above numbers to see which ones have 1 as a remainder:

28/3 = 9 remainder 1

28/6 = 4 remainder 4

28/9 = 3 remainder 1

28/18 = 1 remainder 10

28/27 = 1 remainder 1

There are 3 numbers that will work.

c. 3

No solution

Step-by-step explanation:

y=10+6x

y=6x

10+6x=6x

10=6x-6x

10=0

no solution