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Chunkypants8369
29.07.2019 •
Mathematics
How much pure water must be mixed with 20 liters of a 25% acid solution to reduce it to a 10% acid solution ?
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Ответ:
C1 will be the concentration of the original solution,
V1 will be the volume of the original solution,
C2 will be the concentration o the diluted solution, and
V2 will be the volume of diluted solution.
(25%)(20L) = (10%)V2
V2 = (25%)(20L) / (10%)
Therefore, V2 = 50L
Good luck :)
Ответ:
Mark brainliest please
Hope this helps you