Mathematics: How to solve x in this equation!

Maths is never hard you make...

How to solve x in this equation! - id15165109, natalie2sheffield

joelwilliamjoel

09.01.2022

x = 1/10

Step-by-step explanation:

$2^{x} = 2^{\frac{8}{5} } / 2^{\frac{6}{4} }$

$2^{x} =$ $2^{\frac{8}{5}-\frac{6}{4} }$

$2^{x} =$ $2^{\frac{1}{10} }$

$x = \frac{1}{10}$

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tommybear989

09.01.2022

$\huge \bf༆ Answer ༄$

Let's solve ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf4 {}^{ \frac{ 3 }{4} } \times 2 {}^{ {x}^{} } = 16 {}^{ \frac{2}{5} }$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf(2 {}^{2} ) {}^{ \frac{ 3 }{4} } \times 2 {}^{ {x}^{} } =( 2 {}^{4}) {}^{ \frac{2}{5} }$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf2 {}^{} {}^{ \frac{ 3 }{2} } \times 2 {}^{ {x}^{} } =2 {}^{} {}^{ \frac{8}{5} }$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf2 {}^{} {}^{( \frac{ 3 }{2} + } {}^{ {x)}^{} } =2 {}^{} {}^{ \frac{8}{5} }$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \frac{3}{2} + x = \frac{8}{5}$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf x = \frac{8}{5} - \frac{3}{2}$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf x = \frac{16 - 15}{10}$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf x = \frac{1}{10} \: \: or \: \: \: 0.1$

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