How to write points off a graph as slope intercept form

Slope-intercept form: y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0 , y))

To find the slope(m), use the slope formula and plug in 2 points

(x₂ , y₂) should be the next point after(on the right of) (x₁ , y₁)

If the graph shows the line crossing the y-axis, you can easily find your y-intercept. But if it's not on the graph, you can use

y = mx + b and plug in the slope you found, and plug in a point for (x,y) to find b

Step-by-step explanation:

Hey there!

The equation of line which passes through the point (1,2) is (y-2) = m1(x-1)(i)

The another given equation is y= 2x + 3(ii)

Comparing the equation (ii) with y= mx+c we get;

Slope (m2)= 2.

As per the condition of perpendicular lines, m1*m2 = -1.

m1*2 = -1

Therefore, m1 = -1/2.

Keeping the value of m1 in equation (i) we get;

(y-2) = -1/2(x-1)

y - 2 = -1/2x +1/2

y = -1/2 X + 1/2 + 2

Therefore, the required equation is y = -1/2 X + 5/2.

Hope it helps!