Hurry !

if a cut section of cylindrical tree trunk is 20 feet long and 4 feet around, what is the volume of wood in the section of the tree trunk? (in terms of π)

a) 40π ft^3
b) 80π ft^3
c) 40/π ft^3
d) 80/π ft^3

First we need to find the radius of the cylindrical tree trunk if the circumference C=4 feet: C=2rπ, r=4/(2π)=2/π. Now we find the volume V: V=r^2π*h, where h=20 feet is the height. So we input the numbers: V=(2/π)^2*π*20=(4/π²)*π*20. π in the nominator and the denominator cancel out: V=(4/π)*40=80/π. The volume of the cylindrical tree trunk is V=80/π feet^3

area of parallelogram=base *height