I have two questions to solve

-3x+10=34

13x-4=11x+10-8

-3x + 10 = 34

Subtract 10 from both sides:

-3x = 24

Divide both sides by -3:

X = 24 / -3

X = -8

musiclover10045

Middle School Mathematics 39+20 pts

I have two questions to solve

-3x+10=34

13x-4=11x+10-8

Combine like terms on the right side:

13x -4 = 11x + 2

Subtract 11x from both sides:

2x -4 = 2

Add 4 to both sides:

2x = 6

Divide both sides by 2:

X = 6/2

X = 3

p   …   q   …   ¬q   …   p ∨ ¬q   …   (p ∨ ¬q) ⇒ q

T   …   T   …    F   …        T        …          T

T   …   F   …    T   …        T        …          F

F   …   T   …    F   …        F        …          T

F   …   F   …    T   …        T        …          F

Start with the first two columns, taking every possible pair of True/False for p and q.

¬q is just the negation of q, so True becomes False and False becomes True.

p ∨ q is the logical disjunction, or logical "or". It's True if either p or q is True, and False otherwise. So p ∨ ¬q is True only if either p or ¬q is True.

p ⇒ q is the logical implication. It's True only when both p and q are True, or when p is False. So (p ∨ ¬q) ⇒ q is True when both p ∨ ¬q and q are True, or when p ∨ ¬q is False.