i need friends if you want one join my zoom meeting but I have a math question as well!! Jimmy went to the store to buy bubbles, each pack of bubbles was $0.79. If Jimmy had $36 before going to the store and he bought 34 packs of bubbles, how much money would Jimmy have left??

I would gladly do that but my mom is in my room right now so I can't sorry

Step-by-step explanation:

I think we all need friends during this time xD but sure I’ll be your friend

0.52

Step-by-step explanation:

The complete question is given as follows:

" Of the light bulbs available at a store, 42% are fluorescent, 23% are labeled as long life, and 12% are fluorescent and long life. "

Solution:-

- We will define two events ( A , B ) as follows:

 Event ( A ) : - We randomly select a fluorescent light bulb

 Event ( B ) :- We randomly select a light bulb labelled " long life "

- The respective probabilities of occurance of each event are given as:

                p ( A ) = 0.42  ( 42 % )

                p ( B ) = 0.23  ( 23 % )

- We are asked to compute the conditional probability of picking a fluorescent bulb given that it was labelled " long life ". We can mathematically express the conditional probabilities in terms of events ( A ) and ( B ).

               p ( A / B ) = p ( A & B ) / p ( B )

- The numerator of the conditonal probability: p ( A & B ) is the occurence of both event simultaneously that the chosen/picked light bulb is labelled as " long life " and fluroscent. The probability of simultaneous occurance is given as p ( A & B ) = 0.12 ( 12 % ).

- Therefore, the required conditional probability is:

               p ( A / B ) = 0.12 / 0.23

               p ( A / B ) = 0.52174

- the required answer is to be rounded off to 2 dp. The third dp = 1 < 5. Hence, truncate the 3rd decimal place and on-wards.

- The probability that the selected light bulb is fluorescent given that it is labeled as long life is 0.52