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franklinkaylieg1145
05.12.2021 •
Mathematics
I need help with this problem ;-;
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Ответ:
angles on a straight line = 180 so to find angle 7 you do 180 - 138 = 42 and then angle 6 and 7 are equal so
angle 6 = 42 degrees
Ответ:
y= -3x + 8
Step-by-step explanation:
Put -2x + 6y = -4 into slope-interceltp form
Take the negative reciprocal of the slope.
Use this reciprocal in point-slope form
and you have,
= y= -3x + 8
(EDITED) Steps:
2x+6y = -4
6y=2x - 4
y= 1/3x + 2/3
if two lines are perpendicular,
m1 * m2 + -1
1/3 * m2 = -1
m2 = -3
the line perpendicular to this line is
y = -3x + k ; k ∈ R
the line passes through the point (5,-7)
so,
-7 = -3. (5) +k
-7 = -15 + k
k = 8
∴the equation of a line that passes through the point (5,-7) and is perpendicular to the line -2x+6y=-4 is
y= -3x + 8
Hope this helps, have a nice day/night! :D