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gabrielolivas59
02.09.2019 •
Mathematics
Identify the error in this argument that supposedly shows that if ∃xp(x) ∧ ∃xq(x) is true then ∃x(p(x) ∧ q(x)) is true
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Ответ:
However, ∃x(p(x) ∧ q(x)) means that for the same x=x0, p(x0) is true, and q(x0) is true. This cannot be implied from the first proposition, therefore
∃xp(x) ∧ ∃xq(x) => ∃x(p(x) ∧ q(x)) is a false statement.
Ответ:
25
Step-by-step explanation:
60 = 15
100 = x
now cross multiply so 100*15 is 1500 now divide it by 60 which is 25