Mathematics: If $a:b = 1:3$ and $b$ is a positive, one-digit integer, what is the greatest possible value of $a$?

Step-by-step explanation:to understand thisyou need to know about:linear inequalitytips and formulas:linear equation:y=mx+blet s solve:let s figure out the slopetwo points (2,3),(0,7)y-intercept:7thereforeour linear inequality is...

If $a:b = 1:3$ and $b$ is a positive, one-digit - id138189450, alexandroperez13

Ответ:

zaylelangaigne2006

05.02.2022

Mathematics

Answer is 3

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Work Shown:

a:b = 1:3

a/b = 1/3

a*3 = b*1 ... cross multiply

3a = b

b = 3a

Since b is a one digit number, this means that the largest it can get is 9

$b \le 9\\\\3a \le 9\\\\a \le \frac{9}{3}\\\\a \le 3$

The largest possible value of 'a' is 3

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Ответ:

alondra6190

20.02.2023

Mathematics

$\huge \boxed{ \boxed{\tt y < - 2x + 7 }}$

Step-by-step explanation:

to understand thisyou need to know about:linear inequalitytips and formulas:linear equation:y=mx+b $m = \frac{ y_{2} - y_{1}}{ x_{2} - x_{1}}$ let's solve:

let's figure out the slope

two points (2,3),(0,7)

$m = \frac{ 3 - 7 }{ 2 - 0}$