If a polynomial function f(x) has roots 3 and StartRoot 7 EndRoot, what must also be a root of f(x)?

–√(7) must also be a root of f(x)

Step-by-step explanation:

Given that the roots of an equation is 3 and √(7). This means that x = 3 or √(7). Therefore, the function is definitely going to be:

f(x) = (x – 3)(x² – 7)

This is because we are dealing with √(7) and what brought about √(7) was x² = 7.

If this is the case, we know that x² = 7 will give

x = ±√(7)

Hence, our roots are x = 3 or √(7) or –√(7). Therefore, –√(7) must also be a root of f(x).

The answer is not C

Step-by-step explanation:

I think the answer is D s Pray it will be

UPDATE IT IS D

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