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malikxyo224
25.01.2021 •
Mathematics
If ax2 + bx + c = 0, then x= ? (Hint: Quadratic Formula)
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Ответ:
x = ±![\sqrt{\frac{b^{2} -4ac}{2a}](/tpl/images/1060/9305/4e2ce.png)
It didn't insert but just look up the quadratic formula.
x = ± root [(b²-4ac]/2a]
Ответ:
x = -4.
Step-by-step explanation:
y^2-3y-40/y^2+9y+20
= ( y - 8)(y + 5) / (y + 5)(y + 4)
= (y - 8)/(y + 4)
So the restriction is when x +4 = 0
That is when x = -4.