If BC = 8.3, CD - 6,7, and AD = 11.6, find AB to the nearest tenth.

ab=14.4

Step-by-step explanation:

This is going to be tricky to explain over text, so try to bear with me :) You have the information given above. Let's start with just ad = 11.6 for now. since these are variables, it can also be understood be understood as a times d= 11.6.  Knowing this, we can figure out that d = 11.6/a, when you divide both sides by a. You now have d, so plug (11.6/a) into cd=6.7. You have to do the same thing you did last time, except this time you are aiming to get c by itself. So, multiply both sides by a/11.6 and you get c = (6.7a)/ 11.6.  Guess what, you know c now! so you put (6.7a)/11.6 in for c in the equation given to you earlier, bc =8.3. The math gets a bit messy here, but you basically solve for b here, which, when you crunch the numbers down, ends up being ~14.3705 divided by a. You are looking for ab, so just multiply both sides by a, and round to the nearest tenth so that you have ab= 14.4  

f^-1(x) = 1/5x + 1/5

Step-by-step explanation:

Switch the x and y values:

y = 5x - 1

x = 5y - 1

Put the equation back into y = form:

x = 5y - 1

x + 1 = 5y

1/5x + 1/5 = y

y = 1/5x + 1/5

f^-1(x) = 1/5x + 1/5