If f(x) = 3x-2 and g(x)= x^2 +1, find (f+g)(x).

It's choice D.

Step-by-step explanation:

(f + g)(x) = f(x) + g(x)

= 3x - 2 + x^2 + 1

= x^2 + 3x - 1.

D. x^2+3x-1

Step-by-step explanation:

You have:

f(x) = 3x-2

g(x)= x^2 +1

Then:

(f+g)(x)=f(x)+g(x)

(f+g)(x)=(3x-2)+(x^2+1)

(f+g)(x)=3x-1+x^2 (-2+1=-1)

(f+g)(x)=x^2+3x-1 (ordering terms)

(-3s + 2t)(4s - t).

We use the first term of the first bracket to multiply all of the second bracket and use the second term of the first bracket to multiply all of second bracket again

-3s(4s - t) + 2t(4s - t)

= -12s² + 3st + 8st - 2t²

= -12s² +11st - 2t²