If h= 2f over m+1, solve the equation for f
find the sum of 3b over b+2 and 12 over b+2
solve 3 over 6x + 1 over 2 = 8 over x + 4 over 3
all different questions !

H = 2f / (m+1)
[multiply by (m+1)]
h(m+1) = 2f
[divide by 2]
f = (h (m + 1)) / 2

3b / (b+2) = 12 / (b+2)
[multiply by (b+2)]
3b = 12
[divide by 3]
b = 4

3 / (6x + 1) / 2 = 8 / (x + 4) / 3
[multiply both denominators to mike one denominator]
3 / 8(6x+1) = 8 / 3(x+4)
[expand brackets]
3 / (48x + 8) = 8 / (3x + 12)
[multiply by (48x + 8)]
3 = 8(48x + 8) / (3x+12)
[multiply by (3x+12)]
3(3x +12) = 4(48x + 8)
[simplify]
9x + 36 = 192x + 32
173x = 4
x = 4 / 173

You answer is A. You have to substitute the values of x and y into the equation.

(3*1)= 4-1
 
4-(2*1)=2

(4,1)
(x,y)