tessafargo
04.02.2020 •
Mathematics
If the domain of the function
f (x)=2x^2-8 is (-2,3,5) then the range is
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Ответ:
Step-by-step explanation:
Put the values of x from the domain to the equation of the function
f(x) = 2x² - 8
for x = -2
f(-2) = 2(-2)² - 8 = 2(4) - 8 = 8 - 8 = 0
for x = 3
f(3) = 2(3)² - 8 = 2(9) - 8 = 18 - 8 = 10
for x = 5
f(5) = 2(5)² - 8 = 2(25) - 8 = 50 - 8 = 42
Ответ: