Mathematics: Ignore circled one and work it out please

Ignore circled one and work it out please

Ответ:

laurieburgess804

28.01.2022

a. $\frac{(x-7)}{x^2+x-30}$

Step-by-step explanation:

$\huge \frac{x^2-3x-28}{(x^2+10x+24)(x-5)} \\\\\huge {=\frac{x^2-7x+4x-28}{(x^2+6x+4x+24)(x-5)}}\\\\\huge {=\frac{x(x-7)+4(x-7)}{\{x(x+6)+4(x+6)\}(x-5)}}\\\\\huge {=\frac{(x-7)(x+4)}{(x+6)(x+4)(x-5)}}\\\\\huge {=\frac{(x-7)}{(x+6)(x-5)}}\\\\\huge {=\frac{(x-7)}{x^2+(6-5)x+6(-5)}}\\\\\huge {=\frac{(x-7)}{x^2+x-30}}$

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Ответ:

alexandroperez13

10.05.2021

Mathematics

i only do when im really bored like REALLY bored (pretty rare) but thanks for the points

Step-by-step explanation:

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Ignore circled one and work it out please

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