toricepeda82
24.09.2019 •
Mathematics
Imara used these steps to find the length of the hypotenuse of the right triangle. step 1: find the area of the square with side lengths of 20: 400
step 2: find the area of the square with side lengths of 15: 225
step 3: find the sum of the areas of the two squares: 625
step 4: state the length of the hypotenuse: 625
which best describes imara’s error?
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Ответ:
solution:
as the sides of right triangle that is either base = 15 cm or 20 cm, altitude = 20 cm or 15 cm
so, we have constructed square on the sides having length 15 cm and side having length 20 cm.
area of square having side length 20 cm is (20 cm)²= 400 cm²
area of square having side length 15 cm is (15 cm)² = 225 cm²
sum of areas of two squares = 400 + 225 = 625
so, length of hypotenuse = √625 = 25 cm
fourth statement is incorrect that describes imara's error.
the length of the hypotenuse: ≠ 625. it should be cm
Ответ:
Ответ:
It would be the second option.