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AM28
31.03.2020 •
Mathematics
In a recent year the fuel economy of all passenger vehicles was 19.8 mpg. A trade organization sampled 50 passenger vehicles for fuel economy and obtained a sample mean of 20.1 mpg with standard deviation 2.45 mpg. The sample mean 20.1 exceeds 19.8, but perhaps the increase is only a result of sampling error. Perform the relevant test of hypotheses at the 20% level of significance using the critical value approach. Compute the observed significance of the test. Perform the test at the 20% level of significance using the p-value approach. You need not repeat the first three steps, already done in part (a).
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Ответ:
Answers and Step-by-step explanation:
Hypotheses are:
H o=19.8
H 1 ≠19.8
Here we have following information:
s=2.45, X bar=20.1, n=50
So test statistics will be
t=20.1-19.8/(2.45/
=0.87
Degree of freedom : d f = n - 1 = 50 - 1 =49
Test is two tailed so critical value of the test is -1.30 and 1.30.
Rejection region:
if t < -1.30 and t > 1.30, reject H o
Since test statistics lie in the rejection region so we fail to reject the null hypothesis.
(b)
The observed significance of the test is
P value =0.3885
(c)
Since p value is greater than 0.20 so we fail to reject the null hypothesis.
Ответ:
Translation means it just moves the shape, it does not rotate or reflect the shape in any way.