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chaitanyac90
29.01.2020 •
Mathematics
In a relay race, the probability of the galaxy team winning is 22%. in another unrelated relay race, the probability of the komets team winning is 47%. if the possibility of a tie is not an option, the probability of the komets losing their race and the galaxy winning theirs is ? %
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Ответ:
There is 12% chance that Komets losing their race and the Galaxy winning theirs.
Step-by-step explanation:
Since we have given that
Probability that Galaxy team winning = 22%
Probability that Komets team winning = 47%
Probability that Komets team losing = 100-47=53%
We need to find the probability of the Komets losing and Galaxy winning their game.
So, Probability that Komets losing and Galaxy winning their game is given by
Hence, there is 12% chance that Komets losing their race and the Galaxy winning theirs.
Ответ:
I hope if one of these help.
Step-by-step explanation:
(4 - 3i) + (2 + i )(5 - 2i)
=16 - 2i
If you simplify your answer will be: 16−2i
1) (3+2i)-(1-6i)
2) 4i+3-6+i-1
3) 5i(3-2i)
4) (5+3i)(2-3i)
5) (2+i)(2-i)
1) (3 + 2i) - (1 - 6i)
3 + 2i - 1 + 6i
2 + 8i
2) 4i + 3 - 6 + i - 1
5i - 3 - 1
5i - 4
3) 5i ( 3 - 2i )
15i - 10i^2
15i - 10 ( -1 )
15i + 10
4) ( 5 + 3i ) ( 2 - 3i )
10 - 15i + 6i - 9i^2
10 - 9i - 9i^2
10 - 9i - 9 ( -1 )
10 - 9i + 9
- 9i + 19
5) ( 2 + i ) ( 2 - i )
4 - 2i + 2i - i^2
4 - i^2
4 - (-1)
5
1) 2 + 8i
2) -4 + 5i
3) 10 + 15i
4) 19 - 9i
5) 5
The operations with imaginary numbers are equal to those of the real numbers considering i as a variable, but with a property that allows to simplify the expression more, that is that i squared equals -1. Taking this property into account, we solve the expressions like this:
1) (3 + 2i) - (1-6i) = 3 + 2i - 1 + 6i = 2 + 8i
2) 4i + 3-6 + i-1 = 5i - 4 = -4 + 5i
3) 5i (3-2i) = 5i*3 - 5i*2i = 15i - 10i^2 = 15i - 10(-1) = 15i + 10 = 10 + 15i
4) (5 + 3i) (2-3i) = 5*2 - 5 3i + 3i*2 - 3*3i^2 = 10 - 15i + 6i - 9i^2 = 10 - 9i - 9(-1) = 10 - 9i + 9 = 19 - 9i
5) (2 + i) (2-i) = 2*2 - 2*i + 2*i - i^2 = 4 - 2i + 2i - (-1) = 4 + 1 = 5
I hope one of these help:)