Mathematics: In a right triangle, 0 is an acute angle and cos0= 6/11. Evaluate the other five trigonometric functions of 0.

Step-by-step explanation:In circle with center O, By inscribed angle theorem:...

In a right triangle, 0 is an acute angle and cos0=

Ответ:

nataliaguadaluoupa25

26.01.2022

Mathematics

sin O = √85/11, csc O = 11/√85

cos O = 6/11, sec O = 11/6

tan O = √85/6, cot = 6/√85.

Step-by-step explanation:

cos = adjacent / hypotenuse = 6/11, so the opposite side to angle O

= √(11^2 - 6^2)

= √85.

csc O = 1/sin O

sec O = 1/cos O

cot O = 1/tan O.

0,0(0 оценок)

Ответ:

Najibddahir45

29.11.2022

Mathematics

$(180 - 2x)\degree$

Step-by-step explanation:

In circle with center O, $m\angle BCD = x\degree ... (given) \\$

By inscribed angle theorem:

$m\angle BCD= \frac{1}{2} \times m\widehat {BD} \\\therefore x\degree = \frac{1}{2} \times m\widehat {BD} \\\therefore \widehat {BD} = 2x\degree \\\because m\widehat {BCD}+m\widehat {BD}= 360\degree \\(By\: arc\: sum\: postulate\: of\: a \: circle) \\\therefore m\widehat {BCD}+2x\degree = 360\degree \\\therefore m\widehat {BCD} = 360\degree - 2x\degree \\\\\because m\angle BAD = \frac{1}{2}(m\widehat {BCD} - m\widehat {BD}) \\\\\therefore m\angle BAD = \frac{1}{2}(360\degree - 2x\degree - 2x\degree) \\\\\therefore m\angle BAD = \frac{1}{2}(360\degree - 4x\degree ) \\\\\therefore m\angle BAD = \frac{1}{2}\times 2(180\degree - 2x\degree \\\\ \red {\boxed {\bold {\therefore m\angle BAD =(180- 2x)\degree}}} \\\\$

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In a right triangle, 0 is an acute angle and cos0= 6/11. Evaluate the other five trigonometric functions of 0.

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