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mollietennis
17.03.2020 •
Mathematics
In a survey of a group of men, the heights in the 20-29 age group were normally distributed, with a mean of 69.5inches and a standard deviation of 3.0inches. A study participant is randomly selected. Complete parts (a) through (d) below.
a. Find the probability that a study participant has a height that is less than 66 inches.
b. Find the probability that a study participant has a height that is between 66 and 71 inches.
c. Find the probability that a study participant has a height that is more than 71 inches.
d. Identify any unusual events. Explain your reasoning.
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Ответ:
a)![P(X](/tpl/images/0549/9249/c02cd.png)
And we can find this probability using the normal standard table:
b)![P(66](/tpl/images/0549/9249/8a1bb.png)
And we can find this probability with thi difference:
And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.
c)![P(X71)=P(\frac{X-\mu}{\sigma}\frac{71-\mu}{\sigma})=P(Z\frac{71-69.5}{3.0})=P(z0.5)](/tpl/images/0549/9249/ae2de.png)
And we can find this probability using the complement rule and the normal standard table:
d)![\mu - 2*\sigma = 69.5 -2*3=63.5](/tpl/images/0549/9249/ac9c6.png)
If a value is lower than 63.5 or higher than 75.5 we can consider it as unusual
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Part a
Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:
Where
and ![\sigma=3.0](/tpl/images/0549/9249/10b7c.png)
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability using the normal standard table:
Part b
And we can find this probability with thi difference:
And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.
Part c
And we can find this probability using the complement rule and the normal standard table:
Part d
For this case we can consider as unusual events values above/ below two deviations within the mean:
If a value is lower than 63.5 or higher than 75.5 we can consider it as unusual
Ответ:
Sin f = YW/YX = 8/9
If YW = 24, then for YW/YW to equal 8/9, YX must be 27.