In a triangle ABC two points D,E are taken on BC so that angle BAD=angle DAE=angleCAE. Determine AE if AB=5,BC=10 angle BAC=90. PLEASE HELP I NEED HELP WITHIN TEN MINS PLEASE

AE = 7.5

Step-by-step explanation:

Since <BAC = , then;

<BAD = <DAE = <CAE = (complementary angles)

From ΔABC, applying the Pythagoras theorem to determine the length of side AC;

= +

= +

100 = + 25

= 100 - 25

= 75

AC =

Applying trigonometric function to ΔCAE,

Cos =

AE = × Cos

    = 7.5

Therefore, AE = 7.5

(–3, 3)   then 3 <2(-3) +3 3 < - 3 FALSE
(–2, –2) then -2 <2(-2)+3 -2 < -1 TRUE
(–1, 1)   then 1 <2(-1) +3 1 < 1 FALSE
(0, 1) then 1 <2(0) + 3 1 < 3 TRUE
(2, 5) then 5 <2(2)+3 5< 7 TRUE

answer
(–2, –2)
(0, 1)
(2, 5)