Mathematics: In late June 2012, Survey USA published results of a survey stating that 55% of the 579 randomly sampled Kansas residents planned to set off fireworks on July 4th. Determine the margin of error for the 55% point estimate using a 95% confidence level. The margin of error is: % (please round to the nearest percent)

The equation would be y=5/3 + 5Step-by-step explanation:-5x + 3y = 15+5x +5x3y = 15 + 5x 3y = 5/3x + 5That means start at y = 5, mark your first point. Then move up according to 5/3x...

In late June 2012, Survey USA published results

Ответ:

itssmookie6540

08.02.2022

Mathematics

The Margin of Error E $\simeq$ 4.1 %

Step-by-step explanation:

Given that:

The sample size = 579

The sample proportion $\hat p = 55\%$ = 0.55

From the confidence interval of 95%

The level of significance ∝ = 1 - C.I = 1 - 0.95 = 0.05

The critical value of $Z_{\alpha/2 } = Z_{0.025} = 1.96$

Thus;

The Margin of Error E = $Z_{\alpha/2 } \times \sqrt{{\dfrac {\hat p ( 1 - \hat p }{n}}$

The Margin of Error E = $1.96 \times \sqrt{{\dfrac {0.55 ( 1 - 0.55) }{579}}$

The Margin of Error E = $1.96 \times \sqrt{{\dfrac {0.55 ( 0.45 )}{579}}$

The Margin of Error E = $1.96 \times \sqrt{{\dfrac {0.2475}{579}}$

The Margin of Error E = $1.96 \times \sqrt{{4.2746114 \times 10^{-4}}$

The Margin of Error E = $1.96 \times .020675$

The Margin of Error E = 0.040523

The Margin of Error E $\simeq$ 0.041

The Margin of Error E $\simeq$ 4.1%

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Ответ:

SKYBLUE1015

14.11.2021

Mathematics

The equation would be y=5/3 + 5

Step-by-step explanation:

-5x + 3y = 15

+5x +5x

3y = 15 + 5x

y = 5/3x + 5

That means start at y = 5, mark your first point. Then move up according to 5/3x

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