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charleechristan
30.03.2020 •
Mathematics
In the figure below, \overline{AB}
AB
start overline, A, B, end overline is a diameter of circle PPP.
What is the arc measure of \stackrel{\LARGE{\frown}}{AD}
AD
⌢
A, D, start superscript, \frown, end superscript in degrees?
Solved
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Ответ:
Arc AD = 43°
Step-by-step explanation:
Image is attached.
When an angle subtends from an Arc to the center, the measure of the Arc and the Angle are same. Now, looking at the figure,
Arc AB = 180 (since this is an Arc subtending the diameter)
Arc DC = 90 degrees since the central angle is 90
So,
Arc AD + Arc CB = 180 - 90 = 90
Arc AD and Arc CB have the same measures as the central angle it created (terms in x). So we can write:
Arc AD + Arc CB = 90
7x + 1 + 9x - 7 = 90
We can solve for x:
The central angle AD is:
AD = 7x + 1 = 7(6) + 1 = 43
Also, Arc AD is same, thus:
Arc AD = 43°
Ответ:
Do you have a graph
Step-by-step explanation: