Mathematics: Industry standards suggest that 8 percent of new vehicles require warranty service within the first year. Jones Nissan in Sumter, South Carolina, sold 9 Nissans yesterday. (Round your mean answer to 2 decimal places and the other answers to 4 decimal places.) a. What is the probability that none of these vehicles requires warranty service? b. What is the probability exactly one of these vehicles requires warranty service? c. Determine the probability that exactly two of these vehicles require warranty

Industry standards suggest that 8 percent of new

aliyahaliyah54

20.01.2022

Step-by-step explanation:

Let X be the no of vehicles that require warranty service within I year out of vehicles sold (9) yesterday.

Each vehicle is independent of the other to get warranty service

Hence X is binomial with p=8% = 0.08

So P(X=x) = $9Cx (0.08)^x (1-0.08)^{9-x} ,x=0,1,2...9$

$a) P(X=0) = 0.472161\\b) P(x=1) = 0.3695$

c) P(X=2) = 0.1285

d) Mean = Mean of binomial = np =

9(0.08) = 0.72

Var (x) = npq = 0.6624

Std dev = square root of variance = 0.8139

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SmolBeanPotato

04.03.2022

Step-by-step explanation:

yes it is a fair game because any one don't know what the coin will get, it is based on luck

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