Involving the selection of frozen dinners. assume that there are 15 frozen dinners: 7 pasta, 6 chicken, and 2 seafood dinners. the student selects 5 of them. what is the probability that at least 2 of the dinners selected are pasta dinners?

The probability that at least 2 of the dinners selected are pasta dinners will be 0.8181...

Explanation

Pasta dinners = 7 , Chicken dinners = 6 and Seafood dinners = 2  

The student selects 5 of the total 15 dinners. So, total possible ways for selecting 5 dinners

For selecting at least 2 of them as pasta dinners, the student can select 2, 3, 4 and 5 pasta dinners from total 7 pasta dinners.

So, the possible ways for selecting 2 pasta dinners

The possible ways for selecting 3 pasta dinners

The possible ways for selecting 4 pasta dinners

The possible ways for selecting 5 pasta dinners

Thus, the probability for selecting at least 2 pasta dinners

C. 4.53

Step-by-step explanation:

So we know that the total among these angles measure 180°

(straight lines paralleled with r and s) those lines are 180 degrees.

So subtract 180° - 116° to get rid of the other angle

180° - 116 = 64°

Then use the statement below to identify the value of y.

= +4     It's easier if you add 4 to both sides

         Solve for y

y = 4.53