Mathematics: Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

Is (1, 3) a solution to the system of equations - id1310136708, sabrinakholikov

Ответ:

brevenb375

16.03.2022

The solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

Step-by-step explanation:

we can solve the system of equations to find the value of x and y and then verify if (1,3) is a solution or not.

The system of equation given is:

$y=6x-3\\y=x-2$

Solving:

Let:

$y=6x-3--eq(1)\\y=x-2--eq(2)$

Put value of y from equation 2 into equation 1

$y=6x-3\\Put\:y=x-2\\x-2=6x-3\\x-6x=-3+2\\-5x=-1\\x=\frac{-1}{-5}\\x=\frac{1}{5}$

Now, put value of x in equation 2 to find value of y

$y=x-2\\Put\:x=\frac{1}{5} \\y=\frac{1}{5} -2\\y=\frac{1-2*5}{5} \\y=\frac{1-10}{5}\\ y=\frac{-9}{5}$

So, the solution for given system of equation is: $x=\frac{1}{5}\:and\:y=\frac{-9}{5}$ and ordered pair is: $\mathbf{(\frac{1}{5},\frac{-9}{5})}$

So, (1,3) is not solution to the given system of equations.

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Ответ:

miraclewhipppp

27.10.2021

Mathematics

41.1

Step-by-step explanation:

To find the value of x, we need to use SOH-CAH-TOA. SOH-CAH-TOA is since, cosine, and tangent. The O, A, H stands for opposite, adjacent, and hypotenuse respectively.

Looking at the figure, we see 47°. The labelled angles are adjacent and the hypotenuse. Therefore, we use CAH or cosine.

$cos(47)=\frac{28}{x}$ [multiply both sides by x]

xcos(47)=28 [divide both sides by cos(47)]

$x=\frac{28}{cos(47)}$

When we plug that into a calculator, we get x=41.1.

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Is (1, 3) a solution to the system of equations listed below? (1 point) y= 6x -3 y = x - 2

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