yalley1982
04.08.2019 •
Mathematics
Jacks age is three years more than twice the age of his younger brother jimmy if the sum of their ages is at most 18 find the greatest age that jimmy could be
Solved
Show answers
More tips
- S Science and Technology QR Code: How it Works and Why You Need it?...
- C Computers and Internet Dropbox: What is it and How to Use it...
- H Health and Medicine How to Increase Hemoglobin in the Blood...
- A Animals and plants How to Store Carrots: Tips for Homeowners...
- L Legal consultation Juvenile Justice: Who Needs It?...
- F Family and Home How to Choose the Best Diapers for Your Baby?...
- F Family and Home Parquet or laminate, which is better?...
- L Leisure and Entertainment How to Properly Wind Fishing Line onto a Reel?...
- L Leisure and Entertainment How to Make a Paper Boat in Simple Steps...
- T Travel and tourism Maldives Adventures: What is the Best Season to Visit the Luxurious Beaches?...
Answers on questions: Mathematics
- M Mathematics Which ordered pair is a solution of the question -7x + 3y equals two...
- M Mathematics Kira has completed 26 hours of community service. her goal is to complete at least 90 hours. Write and solve an inequality to show how many more hours, H kira needs to...
- B Biology Some steps in mitosis are shown below in the incorrect order: step a: chromosomes line up at the center of the cell step b: the cell membrane squeezes the middle of the...
- M Mathematics Which detail from the passage BEST supports the underlined statement on page 3? Environments that offer new experlences are best for a young child s brain development,...
- E English NO LINKS NO LINKS What do you do in a Dryfold effective position ANSWER ONLY if you know...
- M Mathematics What’s 12.71 divided 6.2?...
- E English Explain why martin luther king was wise to criticize the white moderator in letter from birmingham jail...
Ответ:
To prove it, subtract 5 from 18 - You'll get 13.
5 x 2 + 3 = 13.
Ответ:
well theres not measurements so i cant help, sorry..
Step-by-step explanation: