Janet can do a job in 3 hours while garry can do the same job in 2 hours. if janet works for an hour before garry began her, how long will it take them to finish the job together?

4/5 hour (48 minutes)

Step-by-step explanation:

Janet works at the rate of ...

(1 job)/(3 hours) = (1/3) job/hour

So, in 1 hour, she has worked 1/3 of the job, leaving 2/3 of the job remaining when Garry shows up.

Garry works at the rate of ...

(1 job)/(2 hours) = 1/2 job/hour

So, together they work at the rate of ...

(1/3 job/hour) + (1/2 job/hour) = (2/6 +3/6) job/hour = 5/6 job/hour

Then the time it takes to do the remaining 2/3 job is ...

(2/3 job)/(5/6 job/hour) = (2/3·6/5) hour = 4/5 hour

It will take 4/5 hour for them to finish the job together.

Number of Small Cones Sold=22

Number of Large Cones Sold=34

Step-by-step explanation:

Suppose,

Number of Small Cones Sold: s

Number of Large Cones Sold: l

For the condition that, larges cones sold were 12 more than small ones, equation would be

and for the total revenue condition of $163

By solving equation (i) and (ii) simultaneously, we get

s=22

and

l=34

Hence, small cones sold would be 22 and large cones sold would be 34.