JL has coordinates J(-6, 1) and L(-4,3).
Find the coordinates of the midpoint.

The coordinates of the mid-point of JL are (-5 , 2)

Step-by-step explanation:

If point (x , y) is the mid-point of a segment whose end-points are and , then and  

∵ JL is a segment

∵ The coordinates of J are (-6 , 1)

∴   = -6 and   = 1

∵ The coordinates of L are (-4 , 3)

∴   = -4 and   = 3

Lets use the rule above to find the mid-point of JL

∵

∴ x = -5

∴ The x-coordinate of the mid-point is -5

∵

∴ y = 2

∴ The y-coordinate of the mid-point is 2

∴ The coordinates of the mid-point of JL are (-5 , 2)

Step-by-step explanation:

f(4) = 42 + 5 =21, f(-10) = (-10)2 +5 = 105 or alternatively f: x → x2 + 5.

The phrase "y is a function of x" means that the value of y depends upon the value of x, so:

y can be written in terms of x (e.g. y = 3x ).

If f(x) = 3x, and y is a function of x (i.e. y = f(x) ), then the value of y when x is 4 is f(4), which is found by replacing x"s by 4"s .

If f(x) = 3x + 4, find f(5) and f(x + 1).

f(5) = 3(5) + 4 = 19

f(x + 1) = 3(x + 1) + 4 = 3x + 7