Jones covered a distance of 50 miles on his first trip. on a later trip he traveled 300 miles while going three times as fast. his new time compared with the old time was: (a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much

(b) twice as much

Step-by-step explanation:

Hi, to answer this question we have to apply the speed formula for each case:

Speed = distance /time

For time:

Time = distance / speed

First trip = 50/x

Where x is the speed of Jones covering that distance.

Last trip =300/ 3x = 100/x

If we compare both times, we can see clearly that the new time compared with the old time was twice as much.

Feel free to ask for more if needed or if you did not understand something.

x = 3/2

Step-by-step explanation:

2(x + 5) = 6x + 4

Open bracket first

2 × x + 2×5 = 6x + 4

2x + 10 = 6x + 4

Rewrite equation

6x + 4 = 2x + 10

Subtract 2x from both sides

6x - 2x + 4 = 2x - 2x + 10

4x + 4 = 10

Subtract 4 from both sides

4x + 4 - 4 = 10 - 4

4x = 6

Divide both sides by 4

4x/4 = 6/4

x = 6/4

Divide both denominator and numerator by 2

x = (6/4) ÷ 2

x = 3/2

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