Mathematics: Jordan bikes at a speed of 8 2/3 mph. how many miles will he bike in 3 hours and 6 minutes?

Jordan bikes at a speed of 8 2/3 mph. how many

Ответ:

jyworthy

15.01.2022

Mathematics

He will bike 26.87 miles.

Step-by-step explanation:

Given:

Jordan bikes at a speed of 8 2/3 mph.

Now, to find the distance he will bike in 3 hours and 6 minutes.

Speed = $8\frac{2}{3}=\frac{26}{3}\ mph.$

Time = 3 hours and 6 minutes

= $180+6=186\ minutes.$

As, 60 minutes = 1 hour.

= $\frac{186}{60} =3.1\ hours.$

So, to get the distance we put formula:

$Distance=speed\times time$

$Distance=\frac{26}{3} \times 3.1$

$Distance=\frac{80.6}{3}$

$Distance=26.87\ miles.$

Therefore, he will bike 26.87 miles.

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Ответ:

Nathaliasmiles

15.01.2022

Mathematics

Jordan will bike 28.67 miles in 3 hours and 6 minutes.

Information given in the question,

Speed of the Jordan's bike = $8\frac{2}{3}$ mph Or $\frac{26}{3}$ mphTime of travelling = 3 hours 6 minute

Since, speed of an object can be calculated by the expression,

Speed = $\frac{\text{Distance}}{\text{Time}}$

From the question,

Time of travelling = 3 hours and 6 minutes

= 3 hours + $\frac{6}{60}$ hours

= 3.1 hours

Substitute these values in the expression,

$\frac{26}{3}=\frac{\text{Distance}}{3.1}$

Distance = $\frac{26\times 3.1}{3}$

= 28.67 miles

Therefore, Jordan will bike 28.67 miles in 3 hours and 6 minutes.

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Ответ:

potatogirl9300

01.02.2022

Mathematics

Step-by-step explanation:

h(t) = (t + 3)² + 5

A) h(t) = (t + 3)² + 5 -2 ≤ t ≤ 0

average rate of change in h over the change in t is given as:

$\frac{h(0)-h(-2)}{0-(-2)}=\frac{(0+3)^2+5-[(-2+3)^2+5]}{0+2}=\frac{14-6}{2} =4$

It does not have a negative average rate of change

B) A) h(t) = (t + 3)² + 5 -4 ≤ t ≤ -3

average rate of change in h over the change in t is given as:

$\frac{h(-3)-h(-4)}{-3-(-4)}=\frac{(-3+3)^2+5-[(-4+3)^2+5]}{-3+4}=\frac{5-6}{1} =-1$

It have a negative average rate of change

c) A) h(t) = (t + 3)² + 5 -3 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(-3)}{4-(-3)}=\frac{(4+3)^2+5-[(-3+3)^2+5]}{4+3}=\frac{54-5}{7} =7$

It does not have a negative average rate of change

D) h(t) = (t + 3)² + 5 1 ≤ t ≤ 4

average rate of change in h over the change in t is given as:

$\frac{h(4)-h(1)}{4-(1)}=\frac{(4+3)^2+5-[(1+3)^2+5]}{4-1}=\frac{54-21}{3} =11$

It does not have a negative average rate of change

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Jordan bikes at a speed of 8 2/3 mph. how many miles will he bike in 3 hours and 6 minutes?

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