Joseph measured a house and made a scale drawing. The scale he used was 11 centimeters :5 meters. If the actual length of the garage is 10 meters, how long is the
garage in the drawing?

The length of the garage on the drawing is 22 cm

Step-by-step explanation:

The scale of the scale drawing = 11 centimeters: 5 meters

The actual length of the garage = 10 meters

The length of the garage in the drawing is found as follows;

5 meters = 500 centimeters

10 meters = 1,000 centimeter

Therefore, the scale of the drawing = 11 cm : 5 m = 11 cm : 500 cm

Let 'a' represent the length of the garage on the drawing, we have;

a : 1,000 cm = 11 cm : 500 cm

Therefore;

The length of the garage on the drawing, a = 22 cm.

The interval as observed from the graph where the height of rock is increasing is (0,3).

Step-by-step explanation:

We are given the following in the question:

A rock is thrown from a 52 foot cliff.

The attached image shows the graph of height of rock y units in time x seconds.

Thus, the x-axis represents time in seconds.

The y-axis represents the height of the rock.

We have to find the interval for which the height of rock is always increasing.

Looking at the graph, the height of rock follows a parabolic pattern that is first the height of rock increases, reaches a maximum value and then decreases.

The interval as observed from the graph where the height of rock is increasing is (0,3).

This can be interpreted as:

From 0 to 3 seconds the height of the rock increases from 52 foot to 180 foot.At 3 second the rock is at maximum height that is 180 foot.After 3 seconds the height of the rock decreases from 180 foot to 0 foot that is ground level.