jobucks9976
09.01.2020 •
Mathematics
Let b1 = [1 - 3] and b2 = [2 - 5]. the set b = {b1, b2} is a basis for r2. let t : r2 rightarrow r2 is a linear transformation such that t(b1) = 4b1 + 4b2 and t(b2) = 8b1 + 5b2. then the matrix of t relative to the basis b is [t]b = [ ], and the matrix of t relative to the standard basis e for r2 is [t]e = [].
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Ответ:
187 sweets
Step-by-step explanation:
8 units - 6 units = 2 units
2 units = 22 sweets
1 unit = 22 sweets ÷ 2
= 11 sweets
Total amount of sweets = 11 sweets × (6 units + 3 units + 8 units) = 11 sweets × 17 = 187 sweets