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14.01.2021 •
Mathematics
Line q passes through the point (4,6)and (0,6). What is the equation for the line which is parpendicular to q and passes through the point (-2,3)
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Ответ:
The equation of the line passing through the points (4, 6) and (0, 6) will be:
y = 6The graph of the equation y = 6 is also attached.
Step-by-step explanation:
The slope-intercept form of the line equation
where
m is the slopeb is the y-interceptGiven the points
(4, 6)(0, 6)Finding the slope between (4, 6)and (0, 6).
Using the formula
Slope = m = [y₂ - y₁] / [x₂ - x₁]
= [6 - 6] / [0 - 4]
= 0 / -4
= 0
Thus, the slope of the line = m = 0
The slope m = 0 means the line is horizontal. Because the slope of the horizontal line is 0.
As the y-values are not changing with respect to the x-values.
Therefore,
The equation of the line passing through the points (4, 6) and (0, 6) will be:
y = 6The graph of the equation y = 6 is also attached.
Ответ:
Statement Reason
1. AB = x + 16 1. Given
BC = 4x + 11
AC = 77
2. AB + BC = AC 2. Segment Addition Postulate
3. x + 16 + 4x + 11 = 77 3. Substitution Property
4. 5x + 27 = 77 4. Simplification (added like terms)
5. 5x = 50 5. Subtraction Property of Equality
6. x = 10 6. Division Property of Equality
7. AB = 10 + 16 7. Substitution Property
8. AB = 26 8. Simplification (added like terms)