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24jameb
05.10.2020 •
Mathematics
Line segment XY has endpoints X(5, 7) and Y-3, 3). Find the equation for the perpendicular bisector of line segment XY
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Ответ:
Option (1)
Step-by-step explanation:
Perpendicular bisector of the segment will pass through the midpoint of the segment joining two points (5, 7) and (-3, 3).
Midpoint of the segment will be,
(x, y) =![(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})](/tpl/images/0788/3987/9b3e5.png)
=![(\frac{5-3}{2},\frac{7+3}{2})](/tpl/images/0788/3987/4d527.png)
= (1, 5)
Slope of the line joining the given points
= ![\frac{y_2-y_1}{x_2-x_1}](/tpl/images/0788/3987/f6758.png)
=![\frac{1}{2}](/tpl/images/0788/3987/9cdae.png)
Let the slope of the line perpendicular to the segment joining the given points is
.
By the property of perpendicular lines,
Since, equation of a line passing through (x', y') and slope 'm' is,
y - y' = m(x - x')
Therefore, equation of the line passing through (1, 5) and slope (-2) will be,
y - 5 = (-2)(x - 1)
y = -2x + 2 + 5
y = -2x + 7
2x + y = 7
Therefore, Option (1) will be the answer.
Ответ:
10
Step-by-step explanation: When multiplying integers,
if the signs are the same, the product is positive.
So a negative times a negative always equals a positive.
Therefore, -5(-2) is 10.