Mai runs each lap in 5 minutes. she will run less than 45 minutes today what are the possible numbers of laps she will run today. write it as a inequality and use n for the number of laps she will run today

The possible number of laps are :

Step-by-step explanation:

Given:

Time taken by Mai to run each lap = 5 minutes

Total number of laps =

Tie taken to run laps = minutes.

Mai runs less than 45 minutes.

So, we have  

We solve for

Dividing both side by 5.

Therefore number of laps is less than 9.

So, the possible number of laps are :

Given:
u = 44 ft/s, the initial upward velocity of the ball

The height in feet after t seconds is
y = 44t - 16t²

Initial time is t₁ = 2 s.
The height at 2 s is
h₁ = 44*2 - 16*(2²) = 24 ft

(i) When the duration is 0.5 s, the final time is
    t₂ = 2 +0.5 = 2.5
    The height at 2.5 s is
     h₂ = 44*2.5 - 16(2.5²) = 10 ft
    The average velocity is
    v = (10 - 24 ft)/(0.5 s) = -28 ft/s
    - 28 ft/s

(ii) When the duration is 001s, then t₂ = 2.1 s
    h₂ = 44*2.1 - 16(2.1²) = 21.84 ft
    The average velocity is
    v = (21.84 - 24)/0.1 = -21.6 ft/s
    - 21.6 ft/s

(iii) When the duration is 0.05s, t₂ = 2.05 s
    h₂ = 44*2.05 - 16(2.05²) = 22.96
   Average velocity is
   v = (22.96 - 24)/.05 = - 20.8 ft/s
     - 20.8 ft/s

(iv) When the duration is 0.01 s, t₂ = 2.01 s
  h₂ = 44*201 - 16(2.01²) = 23.7984 ft
   v = (23.7984 - 24)/0.01 = - 20.16 ft/s
  - 20.16 ft/s

As the duration gets smaller, the computed average velocity approaches the true value at 2 s, because it is the derivative of y with respect to t.