math in a garden there are two type of plant one is of float plant and the other type of plant is flower plant the number of fruit plant is more than flower plant this relation is given in the form of polynomial P(x) =x²-11+24

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shyra94

14.03.2022

Mathematics

The answer is $\sum_{n=0}^{\infty}(-1)^n3^n$

Step-by-step explanation:

Given the pattern 1 - 3 + 9 - 27 + ...

we have to write the sum using summation notation.

As, $1=(-1)^{0}3^0$

$-3=(-1)^{1}3^1$

$9=(-1)^{2}3^2$

$-27=(-1)^{3}3^3$

hence, we can write

1 - 3 + 9 - 27 + ...

= $(-1)^{0}3^0+(-1)^{1}3^1+(-1)^{2}3^2+(-1)^{3}3^3+.....$

= $\sum_{n=0}^{\infty}(-1)^n3^n=\sum_{n=0}^{\infty}(-3)^n$

which is required sigma notation.

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math in a garden there are two type of plant one is of float plant and the other type of plant is flower plant the number of fruit plant is more than flower plant this relation is given in the form of polynomial P(x) =x²-11+24​