Me with algebra 2? ! i am so lost on how to do this! 1.multiply and simplify if possible. four square root of eleven•four square root of ten (1 point) 11four square root of ten 11 10 four square root of one hundred ten 2.what is the simplest form of the expression? cubed root of twenty four times a to the tenth times b to the sixth (1 point) 3a3b2cubed root of two a 2a3bcubed root of a 2a3b2cubed root of three a none of these

Question 1: 
- both squared roots are multiplied by 4, therefore you can regroup: 4·(√11·√10)
- since they are both squared roots, you can multiply the two numbers: 4·√(11·10)
- therefore the answer is: 4·√110

Question 2:
- first thing, you need to factorize the number: 24=2³·3
- then, highlight the exponents multipes of 3: ∛(2³·3·a^9·a·b^6)
- now you can take outside the cubic root everything that has an exponent multiple of 3, dividing the exponents by 3: 2·a³b²·∛3·a

0.134 = 134/1000 = 67/500