Mathematics: Mr. lopez began the two-way table below to display the dominant hand of the students in his first- and second-period classes.dominant handsleft-handedright-handedtotal1st period9282nd period531totalhow many of mr. lopez’s second-period students are right-handed? 14192645 26, you take the total and minus the left handed. pretty simple and i got it right on the test, yah

Mr. lopez began the two-way table below to display

itzyoboyCj

18.01.2023

Step-by-step explanation:

The time it takes for the manticore to travel 10 miles with the wind is given by

$T_1 = \dfrac{10\:\text{mi}}{v_m + v_w}$

where v_m is the speed of the manticore and v_w is the speed of the wind.

Likewise, the time it takes for the manticore to travel 5 miles against the wind is

$T_2 = \dfrac{5\:\text{mi}}{v_m - v_w}$

Since T_1 = T_2, we can write

$\dfrac{10\:\text{mi}}{v_m + v_w} = \dfrac{5\:\text{mi}}{v_m - v_w}$

After cross-multiplying,

10(v_m - v_w) = 5(v_m + v_w)

$\Rightarrow 10v_m - 10v_w = 5v_m + 5v_w$

Collecting similar terms, we get

15v_w = 5v_m

Solving for v_w, we get

$v_w = \dfrac{5}{15}v_m = \dfrac{1}{3}v_m$

$\:\:\:\:\:\:\:=\dfrac{1}{3}(30\:\text{mi/hr}) = 10\:\text{mi/hr}$

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