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ramjand3062
02.11.2020 •
Mathematics
Mr. Murphy is designing a rectangular concrete fire pit. The concrete sides and bottom will be 5 inches thick. The interior length will be 3 times the interior height, and the interior width will be 2 times the interior height. What should the outer dimensions of the fire pit be if the inner volume is to be 6000 cubic inches
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Ответ:
For the outer dimensions: length = 35 inches, width = 25 inches, and height = 15 inches.
Step-by-step explanation:
For the interior;
volume = 6000![in^{3}](/tpl/images/0860/1217/168f8.png)
length, l = 3h
width, w = 2h
height = h
But,
Volume of a cuboid = length x width x height
So that;
6000 = 3h x 2h x h
6000 = 6![h^{3}](/tpl/images/0860/1217/d1bed.png)
Divide through by 6 to have;
1000 =![h^{3}](/tpl/images/0860/1217/d1bed.png)
h =![\sqrt[3]{1000}](/tpl/images/0860/1217/7c899.png)
= 10
Thus, the height is 10 inches. Thus;
length, l = 3h = 3 x 10 = 30 inches
width, w = 2h = 2 x 10 = 20 inches
For the outer dimension, since the concrete sides and bottom would be 5 inches thick. Then its dimension are;
length, l = 30 + 5 = 35 inches
width, w = 20 + 5 = 25 inches
height = 10 + 5 = 15 inches
Ответ:
The image will be the point (6,5)
Step-by-step explanation:
Here, we want to get the image of the point (-5,-6) after the reflection
Mathematically if we reflected a point with the pre-image coordinates (x,y) over the line y = -x; its image becomes (-y, -x)
So, (-5,-6) becomes (6,5)