Need help with problems 16 and 17, please? I'll do brainiac the instructions say to write an equation for the graphs in slope-intercept form.

16) y=-0.5x+3 and 17) y=2x-3

Step-by-step explanation:

16: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Since y=3 at x=0, the y-intercept is (0,3), and b=3.

Slope= where () and () are two points on the line. Choose (0,3) and (2,2):

Slope==-0.5

Plug m=-0.5 and b=3 into y=mx+b:

y=-0.5x+3

17: The slope-intercept form of a line is y=mx+b, where m is the slope, and b is the y-value at the y-intercept.

Because y=-3 at x=0, the y-intercept is (0,-3), and b=-3.

Slope= where () and () are two points on the line. Choose (0,-3) and (1,-1):

Slope===2

Plug m=2 and b=-3 into y=mx+b:

y=2x-3

with speed of 18 feet per second the distance between the twins change.

Step-by-step explanation:

Here we have , Two twins are running away from their mother in opposite directions one with the speed of 10 feet per second and the other with the speed of 8 feet per second. We need to find How and with what speed does the distance between the twins change. Let's find out:

Two twins are running in opposite directions , Let us suppose one twin speed is denoted by , i.e. 10 feet per second

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Now , Speed of other twin is , i.e. -8 feet per second . Minus sign shows the direction as this twin is moving in opposite direction :

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Now, Difference in both speeds will give the change in speed between them :

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Therefore , with speed of 18 feet per second the distance between the twins change.