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dkargbo6034
18.03.2020 •
Mathematics
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Note: Figure not drawn to scale
If a = 33 in and b = 44 in, which of the following is closest to the area of the window?
A.
2,307.3 in2
B.
2,904 in 2
C. 1,452 in2
D.
1,879.65 in?
Solved
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Ответ:
Work Shown:
The rectangle has area 33*44 = 1452 square inches. This is just part of the answer. The semicircle up top must be accounted for as well.
This semicircle has a radius of r = a/2 = 33/2 = 16.5 inches
The area of the semicircle is (1/2)*pi*r^2 = (1/2)*3.14*(16.5)^2 = 427.4325
This adds to the area of the rectangle to get 427.4325+1452 = 1,879.4325
This is fairly close to choice D, though we're a bit off.
The reason for the error is because of how pi = 3.14 is an approximation. A more accurate version is pi = 3.1415926535898
Therefore, the area of the semicircle is closer to
(1/2)*pi*r^2 = (1/2)*3.1415926535898*(16.5)^2 = 427.649299969911
then we add on the rectangle area:
427.649299969911+1452 = 1,879.64929996991
that rounds to 1,879.65
Ответ:
Hello. Please add an image or screenshot, or provide the coordinates of GFE. When you do, I will get back to you.
Step-by-step explanation: