Okay, I pull up, hop out at the after party You and all your friends, yeah, they love to get naughty
Sippin' on that Henn', I know you love that Bacardi (Sonny Digital)
1942, I take you back in that 'Rari

hmmm nice

(x+5) is not a factor of f since f(-5) is not zero.

Step-by-step explanation:

You can find the remainder of f divided by

(x-(-5)), by plugging in -5 into f. We can do this by remainder theorem.

If f(-5 ) is zero then (x-(-5)) is a factor of f.. If it is not zero, then (x-(-5)) is not a factor of f. This is by factor theorem.

Let's try it.

x^3 − 4x^2 + 3x + 7 with x=-5:

(-5)^3 − 4(-5)^2 + 3(-5) + 7

-125-4(25)+-15+7

-125-100-8

-125-108

-233

Since this is not zero then (x-(-5)) is not a factor of f.

Note: (x-(-5)) is the same as saying (x+5).